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std::monostate

Defined in header <variant>.

C++17

struct monostate { };

Unit type intended for use as a well-behaved empty alternative in std::variant. In particular, a variant of non-default-constructible types may list std::monostate as its first alternative: this makes the variant itself default-constructible.

Member functions

pub(constructor)(implicitly declared)trivial implicit default/copy/move constructor
(public member function)
pub(destructor)(implicitly declared)trivial implicit destructor
(public member function)
pub(operator=)(implicitly declared)trivial implicit copy/move assignment
(public member function)

Non-member functions


std::operator==, !=, <, <=, >, >=, <=>(std::monostate)

constexpr bool operator==( monostate, monostate ) noexcept { return true; }     // 1) (since C++17)
constexpr bool operator!=( monostate, monostate ) noexcept { return false; }
constexpr bool operator< ( monostate, monostate ) noexcept { return false; }
constexpr bool operator> ( monostate, monostate ) noexcept { return false; }
constexpr bool operator<=( monostate, monostate ) noexcept { return true; }
constexpr bool operator>=( monostate, monostate ) noexcept { return true; } // 2) (C++17)
constexpr std::strong_ordering operator<=>( monostate, monostate ) noexcept     
{
return std::strong_ordering::equal;
} // 2) (since C++20)

All instances of std::monostate compare equal.

The <, <=, >, >=, and != operators are synthesized from operator<=> and operator== respectively. (since C++20)


Helper classes


std::hash<std::monostate>

template <>
struct std::hash<monostate>; // 2) (since C++17)

Specializes the std::hash algorithm for std::monostate.


Example

#include <cassert>
#include <iostream>
#include <variant>

struct S
{
S(int i) : i(i) {}
int i;
};

int main()
{
// Without the monostate type this declaration will fail.
// This is because S is not default-constructible.
std::variant<std::monostate, S> var;
assert(var.index() == 0);

try
{
std::get<S>(var);
// throws! We need to assign a value
}
catch(const std::bad_variant_access& e)
{
std::cout << e.what() << '\n';
}

var = 42;
std::cout
<< "std::get: "
<< std::get<S>(var).i << '\n'
<< "std::hash: "
<< std::hex << std::showbase
<< std::hash<std::monostate>{}(std::monostate{})
<< '\n';
}
Possible Result
std::get: wrong index for variant
std::get: 42
std::hash: 0xffffffffffffe19f

std::monostate

Defined in header <variant>.

C++17

struct monostate { };

Unit type intended for use as a well-behaved empty alternative in std::variant. In particular, a variant of non-default-constructible types may list std::monostate as its first alternative: this makes the variant itself default-constructible.

Member functions

pub(constructor)(implicitly declared)trivial implicit default/copy/move constructor
(public member function)
pub(destructor)(implicitly declared)trivial implicit destructor
(public member function)
pub(operator=)(implicitly declared)trivial implicit copy/move assignment
(public member function)

Non-member functions


std::operator==, !=, <, <=, >, >=, <=>(std::monostate)

constexpr bool operator==( monostate, monostate ) noexcept { return true; }     // 1) (since C++17)
constexpr bool operator!=( monostate, monostate ) noexcept { return false; }
constexpr bool operator< ( monostate, monostate ) noexcept { return false; }
constexpr bool operator> ( monostate, monostate ) noexcept { return false; }
constexpr bool operator<=( monostate, monostate ) noexcept { return true; }
constexpr bool operator>=( monostate, monostate ) noexcept { return true; } // 2) (C++17)
constexpr std::strong_ordering operator<=>( monostate, monostate ) noexcept     
{
return std::strong_ordering::equal;
} // 2) (since C++20)

All instances of std::monostate compare equal.

The <, <=, >, >=, and != operators are synthesized from operator<=> and operator== respectively. (since C++20)


Helper classes


std::hash<std::monostate>

template <>
struct std::hash<monostate>; // 2) (since C++17)

Specializes the std::hash algorithm for std::monostate.


Example

#include <cassert>
#include <iostream>
#include <variant>

struct S
{
S(int i) : i(i) {}
int i;
};

int main()
{
// Without the monostate type this declaration will fail.
// This is because S is not default-constructible.
std::variant<std::monostate, S> var;
assert(var.index() == 0);

try
{
std::get<S>(var);
// throws! We need to assign a value
}
catch(const std::bad_variant_access& e)
{
std::cout << e.what() << '\n';
}

var = 42;
std::cout
<< "std::get: "
<< std::get<S>(var).i << '\n'
<< "std::hash: "
<< std::hex << std::showbase
<< std::hash<std::monostate>{}(std::monostate{})
<< '\n';
}
Possible Result
std::get: wrong index for variant
std::get: 42
std::hash: 0xffffffffffffe19f