std::ranges::minmax_element() algorithm
- od C++20
- Simplified
- Detailed
// (1)
constexpr minmax_element_result<I>
minmax_element( I first, S last, Comp comp = {}, Proj proj = {} );
// (2)
constexpr minmax_element_result<ranges::borrowed_iterator_t<R>>
minmax_element( R&& r, Comp comp = {}, Proj proj = {} );
The type of arguments are generic and have the following constraints:
I
-std::forward_iterator
S
-std::sentinel_for<I>
R
-std::ranges::forward_range
Comp
:- (1) -
std::indirect_strict_weak_order<std::projected<I, Proj>>
- (2) -
std::indirect_strict_weak_order<std::projected<ranges::iterator_t<R>, Proj>>
- (1) -
Proj
- (none)
The Proj
and Comp
template arguments have the following default types: std::identity
, ranges::less
for all overloads.
// (1)
template<
std::forward_iterator I,
std::sentinel_for<I> S,
class Proj = std::identity,
std::indirect_strict_weak_order<std::projected<I, Proj>> Comp = ranges::less
>
constexpr minmax_element_result<I>
minmax_element( I first, S last, Comp comp = {}, Proj proj = {} );
// (2)
template<
ranges::forward_range R,
class Proj = std::identity,
std::indirect_strict_weak_order<std::projected<ranges::iterator_t<R>, Proj>> Comp = ranges::less
>
constexpr minmax_element_result<ranges::borrowed_iterator_t<R>>
minmax_element( R&& r, Comp comp = {}, Proj proj = {} );
With the helper types defined as follows:
template< class I >
using minmax_element_result = ranges::min_max_result<I>;
-
(1) Finds the smallest and largest element in the range [
first
;last
). -
(2) Same as (1), but uses
r
as the source range, as if usingranges::begin(r)
asfirst
andranges::end(r)
aslast
.
The function-like entities described on this page are niebloids.
Parameters
first last | The range to find the smallest and largest value in. |
r | The range to find the smallest and largest value in. |
comp | Comparison to apply to the projected elements. |
proj | Projection to apply to the elements. |
Return value
An object consisting of an iterator to the smallest element as the first element and an iterator to the greatest element as the second.
Returns { first, first }
if the range is empty.
If several elements are equivalent to the smallest element, the iterator to the first such element is returned.
If several elements are equivalent to the largest element, the iterator to the last such element is returned.
Complexity
Given N
as ranges::distance(first, last)
:
At most max(floor((3 / 2) * (N − 1)), 0)
applications of the comparison and twice as many applications of the projection.
Exceptions
(none)
Possible implementation
minmax_element(1) and minmax_element(2)
struct minmax_element_fn
{
template<std::forward_iterator I, std::sentinel_for<I> S, class Proj = std::identity,
std::indirect_strict_weak_order<std::projected<I, Proj>> Comp = ranges::less>
constexpr ranges::minmax_element_result<I>
operator()(I first, S last, Comp comp = {}, Proj proj = {}) const
{
auto min = first, max = first;
if (first == last || ++first == last) {
return {min, max};
}
if (std::invoke(comp, std::invoke(proj, *first), std::invoke(proj, *min))) {
min = first;
} else {
max = first;
}
while (++first != last) {
auto i = first;
if (++first == last) {
if (std::invoke(comp, std::invoke(proj, *i), std::invoke(proj, *min))) {
min = i;
}
else if (!(std::invoke(comp, std::invoke(proj, *i), std::invoke(proj, *max)))) {
max = i;
}
break;
} else {
if (std::invoke(comp, std::invoke(proj, *first), std::invoke(proj, *i))) {
if (std::invoke(comp, std::invoke(proj, *first), std::invoke(proj, *min))) {
min = first;
}
if (!(std::invoke(comp, std::invoke(proj, *i), std::invoke(proj, *max)))) {
max = i;
}
} else {
if (std::invoke(comp, std::invoke(proj, *i), std::invoke(proj, *min))) {
min = i;
}
if (!(std::invoke(comp, std::invoke(proj, *first), std::invoke(proj, *max)))) {
max = first;
}
}
}
}
return {min, max};
}
template<ranges::forward_range R, class Proj = std::identity,
std::indirect_strict_weak_order<
std::projected<ranges::iterator_t<R>, Proj>> Comp = ranges::less>
constexpr ranges::minmax_element_result<ranges::borrowed_iterator_t<R>>
operator()(R&& r, Comp comp = {}, Proj proj = {}) const
{
return (*this)(ranges::begin(r), ranges::end(r), std::ref(comp), std::ref(proj));
}
};
inline constexpr minmax_element_fn minmax_element;
Examples
#include <algorithm>
#include <iostream>
#include <iterator>
namespace rng = std::ranges;
int main()
{
const auto v = {3, 9, 1, 4, 1, 2, 5, 9};
const auto [min, max] = rng::minmax_element(v);
std::cout
<< "min = " << *min << ", at [" << rng::distance(v.begin(), min) << "]\n"
<< "max = " << *max << ", at [" << rng::distance(v.begin(), max) << "]\n";
}
min = 1, at [2]
max = 9, at [7]
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