std::deque insert() method
- since C++11
- until C++11
// (1) Non const version only
iterator insert( const_iterator pos, const T& value );
// (2) Non const version only
iterator insert( const_iterator pos, T&& value );
// (3) Non const version only
iterator insert( const_iterator pos, size_type count, const T& value );
// (4) Non const version only
template< class InputIt >
iterator insert( const_iterator pos, InputIt first, InputIt last );
// (5) Non const version only
iterator insert( const_iterator pos, std::initializer_list<T> ilist );
// (1) Non const version only
iterator insert( iterator pos, const T& value );
// (3) Non const version only
void insert( iterator pos, size_type count, const T& value );
// (4) Non const version only
template< class InputIt >
void insert( iterator pos, InputIt first, InputIt last );
Inserts element(s) into the container, if the container doesn't already contain an element with an equivalent key.
-
(1-2) Inserts
value
beforepos
. -
(3) Inserts
count
copies of the value beforepos
. -
(4) Inserts elements from range [ first; last ) before
pos
.- since C++11
- until C++11
This overload participates in overload resolution only if
InputIt
qualifies asLegacyInputIterator
, to avoid ambiguity with the overload (3).This overload has the same effect as overload (3) if
InputIt
is an integral type.Undefined behaviourThe behavior is undefined if
first
andlast
are iterators into*this
. -
(5) Inserts elements from initializer list
ilist
beforepos
.Undefined behaviourAll iterators, including the past-the-end iterator, are invalidated. References are invalidated too, unless
pos == begin()
orpos == end()
, in which case they are not invalidated.
Parameters
pos
- iterator before which the content will be inserted. pos may be theend()
iteratorvalue
- element value to insertcount
- number of elemnts to insertfirst
,last
- range of elements to insertilist
- initializer list to insert the values from
Type requirements
- (1) -
T
must meet the requirements ofCopyAssignable
andCopyInsertable
. - (2) -
T
must meet the requirements ofMoveAssignable
andMoveInsertable
. - (3) -
T
must meet the requirements ofCopyAssignable
andCopyInsertable
. - (4-5) -
T
must meet the requirements ofEmplaceConstructible
. -
- since C++17
(4-5) -
T
must meet the requirements ofSwappable
,MoveAssignable
,MoveConstructible
andMoveInsertable
.
Return value
- (1-2) Iterator pointing to the inserted value.
- (3) Iterator pointing to the first element inserted, or
pos
ifcount == 0
. - (4) Iterator pointing to the first element inserted, or
pos
iffirst == last
. - (5) Iterator pointing to the first element inserted, or
pos
ifilist
is empty.
Complexity
For all of the below N
is std::min(std::distance(pos, begin()), std::distance(pos, end()))
- (1-2) Linear in the lesser of the distances between
pos
and either of the ends of the container - O(N). - (3) Linear in
count
+ linear in the lesser of the distances betweenpos
and either of the ends of the container - O(count + N). - (4) Linear in
std::distance(first, last)
+ linear in the lesser of the distances betweenpos
and either of the ends of the container - O(std::distance(first, last) + N). - (5) Linear in
ilist.size()
+ linear in the lesser of the distances betweenpos
and either of the ends of the container - O(ilist.size() + N).
Exceptions
If an exception is thrown when inserting a single element at either end, this function has no effect (strong exception guarantee).
Example
#include <iostream>
#include <iterator>
#include <deque>
void print(int id, const std::deque<int>& container)
{
std::cout << id << ". ";
for (const int x: container)
std::cout << x << ' ';
std::cout << '\n';
}
int main ()
{
std::deque<int> c1(3, 100);
print(1, c1);
auto it = c1.begin();
it = c1.insert(it, 200);
print(2, c1);
c1.insert(it, 2, 300);
print(3, c1);
// reset `it` to the begin:
it = c1.begin();
std::deque<int> c2(2, 400);
c1.insert(std::next(it, 2), c2.begin(), c2.end());
print(4, c1);
int arr[] = {501, 502, 503};
c1.insert(c1.begin(), arr, arr + std::size(arr));
print(5, c1);
c1.insert(c1.end(), {601, 602, 603});
print(6, c1);
}
1. 100 100 100
2. 200 100 100 100
3. 300 300 200 100 100 100
4. 300 300 400 400 200 100 100 100
5. 501 502 503 300 300 400 400 200 100 100 100
6. 501 502 503 300 300 400 400 200 100 100 100 601 602 603
Hover to see the original license.