std::remove_if() algorithm
- since C++20
- since C++17
- until C++17
// (1)
template< class ForwardIt, class UnaryPredicate >
constexpr ForwardIt remove_if( ForwardIt first, ForwardIt last, UnaryPredicate p );
// (2)
template< class ExecutionPolicy, class ForwardIt, class UnaryPredicate >
ForwardIt remove_if( ExecutionPolicy&& policy,
ForwardIt first, ForwardIt last, UnaryPredicate p );
// (1)
template< class ForwardIt, class UnaryPredicate >
ForwardIt remove_if( ForwardIt first, ForwardIt last, UnaryPredicate p );
// (2)
template< class ExecutionPolicy, class ForwardIt, class UnaryPredicate >
ForwardIt remove_if( ExecutionPolicy&& policy,
ForwardIt first, ForwardIt last, UnaryPredicate p );
// (1)
template< class ForwardIt, class UnaryPredicate >
ForwardIt remove_if( ForwardIt first, ForwardIt last, UnaryPredicate p );
Removes all elements satisfying specific criteria from the range [first
; last
) and returns a past-the-end iterator for the new end of the range.
-
(1) Removes all elements for which predicate
p
returnstrue
. -
(2) Same as (1), but executed according to
policy
.Overload ResolutionThese overloads participate in overload resolution only if
std::is_execution_policy_v<std::decay_t<ExecutionPolicy>>
(until C++20)std::is_execution_policy_v<std::remove_cvref_t<ExecutionPolicy>>
(since C++20) istrue
.
- since C++11
- until C++11
Removing is done by shifting (by means of move assignment (since C++11)copy assignment (until C++11)) the elements in the range in such a way that the elements that are not to be removed appear in the beginning of the range.
Relative order of the elements that remain is preserved and the physical size of the container is unchanged.
Iterators pointing to an element between the new logical end and the physical end of the range are still dereferenceable, but the elements themselves have unspecified values (as per MoveAssignable post-condition). (since C++11)
Parameters
first last | The range of elements to process. |
policy | The execution policy to use. See execution policy for details. |
p | Unary predicate which returns The expression |
Type requirements
ForwardIt | LegacyForwardIterator |
UnaryPredicate | Predicate |
Return value
Past-the-end iterator for the new range of values (if this is not end
, then it points to an unspecified value, and so do iterators to any values between this iterator and end
).
Complexity
Given N
as std::distance(first, last)
:
At most N applications of predicate p
.
Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception and
ExecutionPolicy
is one of the standard policies,std::terminate
is called. For any otherExecutionPolicy
, the behavior is implementation-defined. - If the algorithm fails to allocate memory,
std::bad_alloc
is thrown.
Possible implementation
remove_if (1)
template<class ForwardIt, class UnaryPredicate>
ForwardIt remove_if(ForwardIt first, ForwardIt last, UnaryPredicate p)
{
first = std::find_if(first, last, p);
if (first != last)
for (ForwardIt i = first; ++i != last;)
if (!p(*i))
*first++ = std::move(*i);
return first;
}
Notes
A call to remove_if is typically followed by a call to a container's erase member function, which erases the unspecified values and reduces the physical size of the container to match its new logical size. These two invocations together constitute a so-called Erase–remove_if idiom, which can be achieved by the free function std::erase that has overloads for all standard sequence containers, or std::erase_if that has overloads for all standard containers (since C++20)
The similarly-named container member functions list::remove_if, list::remove_if_if, forward_list::remove_if, and forward_list::remove_if_if erase the remove_ifd elements.
These algorithms cannot be used with associative containers such as std::set and std::map because their iterator types do not dereference to MoveAssignable types (the keys in these containers are not modifiable).
Examples
The following code remove_ifs all spaces from a string by shifting all non-space characters to the left and then erasing the extra. This is an example of Erase-remove idiom.
#include <algorithm>
#include <cctype>
#include <iostream>
#include <string>
#include <string_view>
int main()
{
std::string str1 {"Text with some spaces"};
auto noSpaceEnd = std::remove_if(str1.begin(), str1.end(), ' ');
// The spaces are remove_ifd from the string only logically.
// Note, we use view, the original string is still not shrunk:
std::cout << std::string_view(str1.begin(), noSpaceEnd)
<< " size: " << str1.size() << '\n';
str1.erase(noSpaceEnd, str1.end());
// The spaces are remove_ifd from the string physically.
std::cout << str1 << " size: " << str1.size() << '\n';
std::string str2 = "Text\n with\tsome \t whitespaces\n\n";
str2.erase(std::remove_if_if(str2.begin(),
str2.end(),
[](unsigned char x) { return std::isspace(x); }),
str2.end());
std::cout << str2 << '\n';
}
Textwithsomespaces size: 23
Textwithsomespaces size: 18
Textwithsomewhitespaces
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