std::unordered_set find() method

since C++20

// (1) Non const version
iterator find( const Key& key );

// (2) Const version
const_iterator find( const Key& key ) const;

// (3) Non const version
template< class K >
iterator find( const K& x );

// (4) Const version
template< class K >
const_iterator find( const K& x ) const;

since C++11

// (1) Non const version
iterator find( const Key& key );

// (2) Const version
const_iterator find( const Key& key ) const;

• (1-2) Finds an element with key equivalent to key.
• (3-4) Finds an element with key that compares equivalent to the value x. This overload participates in overload resolution only if Hash::is_transparent and KeyEqual::is_transparent are valid and each denotes a type. This assumes that such Hash is callable with both K and Key type, and that the KeyEqual is transparent, which, together, allows calling this function without constructing an instance of Key.

Parameters

• key - key value of the elements to count
• x - a value of any type that can be transparently compared with a key

Return value

Iterator to an element with key equivalent to key. If no such element is found, past-the-end (see end()) iterator is returned.

Complexity

Average case, constant - O(1).
Worst case, linear in the size of the container - O(size()).

Exceptions

(none)

Notes

Feature testing macro: __cpp_lib_generic_unordered_lookup (for overload (3-4)).

Example

Main.cpp

#include <unordered_set>
#include <iostream>
 
int main()
{  
// simple comparison demo
    std::unordered_set<int> example = {1, 2, 3, 4};
 
    auto search = example.find(2);
    if (search != example.end()) {
        std::cout << "Found " << (*search) << '\n';
    } else {
        std::cout << "Not found\n";
    }
 
 
 
}

Possible output

Found 2 b